How many atoms of Nitrogen are in 4(NH₄)₂CrO₄ ?
A. 1
B. 2
C. 8
D. 4
There are a couple of ways to approach this problem, but one common method is to count the number of nitrogen atoms in each molecule of NH₄, and then multiply that by the total number of NH₄ molecules in the compound.
Each NH₄ molecule contains one nitrogen atom, so 4(NH₄)₂ contains a total of 4 x 2 = 8 NH₄ molecules.
Therefore, the total number of nitrogen atoms in the compound is:
8 NH₄ x 1 N per NH₄ = 8 N atoms
So the answer is (C) 8.
To determine the number of atoms of nitrogen in the compound 4(NH₄)₂CrO₄, we need to count the number of nitrogen atoms in one ammonium ion (NH₄⁺) and then multiply it by the coefficient in front of the compound.
In the ammonium ion (NH₄⁺), there is one nitrogen atom (N). Each ammonium ion has a total of four hydrogen atoms (H). The subscript 2 in (NH₄)₂ means there are two ammonium ions.
Therefore, in one mole of (NH₄)₂CrO₄, there are (1 N atom * 2 NH₄ ions) = 2 nitrogen atoms.
Since the coefficient in front of the compound is 4, we multiply the number of nitrogen atoms by 4:
Number of nitrogen atoms = 2 nitrogen atoms * 4 = 8 nitrogen atoms
So, the correct answer is C. 8.
To determine the number of nitrogen atoms in 4(NH₄)₂CrO₄, we need to count the number of nitrogen atoms in one formula unit of (NH₄)₂CrO₄ and then multiply it by 4.
In one formula unit of (NH₄)₂CrO₄, there are 2 nitrogen atoms.
So, multiplying it by 4 gives us:
2 nitrogen atoms x 4 = 8 nitrogen atoms
Therefore, the correct answer is C. 8.