At 20°c kerosene and tetraoxosulphate(vi) acid have the same volume of 500cm. What will be the difference in volumes of liquids at 0°c
To find the difference in volumes of the liquids at 0°C, we need to use the coefficient of volume expansion, which describes the change in volume of a liquid as a result of a change in temperature. The formula for this is:
ΔV = V₀ * β * ΔT,
where ΔV is the change in volume, V₀ is the initial volume, β is the coefficient of volume expansion, and ΔT is the change in temperature.
The coefficients of volume expansion for kerosene and tetraoxosulphate(VI) acid are as follows:
β_kerosene = 0.00095 /°C
β_tetraoxosulphate(VI)_acid = 0.00030 /°C
ΔT = 0°C - 20°C = -20°C
Now, we can calculate the change in volume for each liquid.
ΔV_kerosene = 500 cm³ * 0.00095 /°C * -20°C = -9.5 cm³
ΔV_tetraoxosulphate(VI)_acid = 500 cm³ * 0.00030 /°C * -20°C = -3 cm³
Now we can find the difference in volumes of the liquids at 0°C:
V_kerosene_0°C = V₀ + ΔV_kerosene = 500 cm³ - 9.5 cm³ = 490.5 cm³
V_tetraoxosulphate(VI)_acid_0°C = V₀ + ΔV_tetraoxosulphate(VI)_acid = 500 cm³ - 3 cm³ = 497 cm³
Difference in volumes of liquids at 0°C = |V_kerosene_0°C - V_tetraoxosulphate(VI)_acid_0°C| = |490.5 cm³ - 497 cm³| = 6.5 cm³