The 5term of an exponentail sequence is greater than the 4th tetm by 131\2al and the 4th term is greater than the 3rd by 9 . Find the 1st term, common ratio

131\2al

what on earth is that?

T5 = a r^(5-1) = a r^4
T4 = a r^3
so
a r^4 - a r^3 = whatever that is = a r^3 (r-1) equation 1

a r*3 - a r^2 = 9 so a r^2 (r-1) = 9 equation 2

solve for the two unknowns, a and r