what is the value of (n) ?
(n+3)! = 5040
the prime factorization of 5040 = 2x2x2x2x3x3x5x7
since the ! function involves the multiplication of consecutive integers, it makes sense to arrange these factors so they form consecutive numbers.
I got 2,3,4,5,6, and 7
and sure enough 7!=5040
so (n+3)!=7!
n+3=7 and n=4
An even easier way would be to just try some factorial values. It does not take much to realize that 7!=5040
thanks
i need help on my algebra homework..we are working on radicals and ex. of a question would be..
7*the square root of 2
well thank you..
-carmen
You're welcome, Carmen! I'm glad I could help you with your previous question. Now, let's tackle this algebra homework!
When it comes to multiplying a number by a square root, you can treat it like any other number. So in this case, 7 times the square root of 2 is simply 7√2. It's as easy as that!
If you have any more algebra questions or any other topic you'd like to add a sprinkle of humor to, feel free to ask!
To simplify the expression 7 * √2, we can multiply the whole number 7 by the square root of 2.
7 * √2 can also be written as √(7^2 * 2).
√(7^2 * 2) simplifies to √49 * √2.
√49 is equal to 7, so √49 * √2 = 7 * √2.
Therefore, 7 * √2 cannot be simplified any further, and the final answer is 7√2.
I hope this helps with your algebra homework! If you have any more questions, feel free to ask.
To find the value of (n) in the equation (n+3)! = 5040, we can start by finding the prime factorization of 5040, which is 2 * 2 * 2 * 2 * 3 * 3 * 5 * 7.
Next, since the factorial function (!) involves the multiplication of consecutive integers, we want to arrange these factors in a way that forms consecutive numbers. In this case, we can group the factors as follows: 2, 3, 4, 5, 6, and 7.
We know that 7! (or 7 factorial) is equal to 7 * 6 * 5 * 4 * 3 * 2 * 1, which is 5040. Therefore, we can conclude that (n+3)! = 7!.
To find the value of (n), we subtract 3 from both sides of the equation:
n + 3 = 7
Subtracting 3 from both sides gives us:
n = 7 - 3
n = 4
So the value of (n) in the equation is 4.
As for your question about algebra and radicals, if you need help with a specific problem like 7 times the square root of 2, we can certainly help you with that!
To simplify 7 times the square root of 2, you can multiply the numbers outside the radical (7) by the numbers inside the radical (2).
Therefore, 7 times the square root of 2 is equal to 7√2. This is the simplest form of the expression.