Calculate the mass of silver trioxonitrate in500cm3 of0.01m AgNo3 in gramme.
To calculate the mass of silver trioxonitrate (AgNO3) in 500 cm3 of 0.01 M AgNO3, we need to use the formula:
mass = concentration x volume x molar mass
where:
- concentration = 0.01 M (given)
- volume = 500 cm3 = 0.5 L (given)
- molar mass of AgNO3 = 107.87 g/mol (from periodic table)
Substituting the values, we get:
mass = 0.01 x 0.5 x 107.87
mass = 5.3935 g
Therefore, the mass of silver trioxonitrate in 500 cm3 of 0.01 M AgNO3 is 5.3935 grams.
To calculate the mass of silver trioxonitrate (AgNO3) in 500 cm³ of 0.01M AgNO3 solution, you need to use the formula:
Mass (g) = Concentration (M) × Volume (L) × Molar Mass (g/mol)
Given:
Concentration (M) = 0.01M
Volume (L) = 500 cm³ = 500/1000 L = 0.5 L (since 1 L = 1000 cm³)
Molar Mass of AgNO3 = Ag (107.87 g/mol) + N (14.01 g/mol) + 3O (16.00 g/mol) = 12.07 g/mol
Now, substituting the given values into the formula:
Mass (g) = 0.01M × 0.5 L × 169.87 g/mol
Mass (g) = 0.0084935 g
Therefore, the mass of silver trioxonitrate in 500 cm³ of 0.01M AgNO3 solution is approximately 0.0085 g.
To calculate the mass of silver trioxonitrate (AgNO3) in 500 cm3 of a 0.01 M AgNO3 solution, we need to follow these steps:
Step 1: Calculate the number of moles of AgNO3 present in the solution.
First, we need to find the concentration of AgNO3 in moles per liter (Molarity, M).
0.01 M means there are 0.01 moles of AgNO3 per liter.
Since we have 500 cm3 of solution, we need to convert it to liters:
500 cm3 = 500/1000 = 0.5 liters
Now we can calculate the number of moles of AgNO3:
moles of AgNO3 = Molarity x Volume (in liters)
moles of AgNO3 = 0.01 mol/L x 0.5 L
moles of AgNO3 = 0.005 moles
Step 2: Calculate the molar mass of AgNO3.
The molar mass of AgNO3 can be calculated by adding the atomic masses of silver (Ag), nitrogen (N), and oxygen (O):
Ag = 107.87 g/mol
N = 14.01 g/mol
O = 16.00 g/mol (x3, since there are three oxygen atoms in AgNO3)
Molar mass of AgNO3 = Ag + N + (O x 3)
Molar mass of AgNO3 = 107.87 g/mol + 14.01 g/mol + (16.00 g/mol x 3)
Molar mass of AgNO3 = 107.87 g/mol + 14.01 g/mol + 48.00 g/mol
Molar mass of AgNO3 = 169.88 g/mol
Step 3: Calculate the mass of AgNO3.
We can now calculate the mass of AgNO3 using the number of moles and the molar mass:
mass of AgNO3 = moles x molar mass
mass of AgNO3 = 0.005 moles x 169.88 g/mol
mass of AgNO3 = 0.8494 g
Therefore, the mass of silver trioxonitrate (AgNO3) in 500 cm3 of 0.01 M AgNO3 solution is approximately 0.8494 grams.