A,B,andC care point in the same horizontal plane . The bearing of B from A is 160 and the bearing of C from B is 050.if /AB/=6 and/BC/=4, find the/AC/, The bearing of C from A correct nearest degree

to find AC, use the law of cosines.

AC^2 = 6^2 + 4^2 - 2*6*4 cos70°
C's bearing is 121°