suppose you can factor x^2+bx+c as (x+p)(x+q). If c>0, what could be possible values of p and q?
a. p=5 ,q=-8
b. p=-2 ,q=6
c. p=-4 ,q=-7
d. p=-13 ,q=1
you were wrong
i also need another answer
suppose you can factor x^2+bx+c as (x+p)(x+q). If c<0, what could be possible values of p and q?
a. p=-3 ,q=7
b. p=11 ,q=4
c. p=-2 ,q=-5
d. p=1 ,q=10
AAAaannndd the bot gets it wrong yet again!
since c=pq, that means that p and q have opposite signs.
That leaves only
a. p=5 ,q=-8
b. p=-2 ,q=6
d. p=-13 ,q=1
a. p=-3 ,q=7