A bag contain 10 balls of which 6 are red and the rest are white and blue of equal number, I'd a ball is pick at at random find the probability as it's (I) either white or red (ii) not red (iii) blue or red (iv) white
AAAaannndd the bot gets it wrong yet again!
2 each of blue and white, so
P(w|r) = P(b|r) = (6+2)/10 = 4/5
(i) P(white or red) = 6/10 = 0.6
(ii) P(not red) = 4/10 = 0.4
(iii) P(blue or red) = 6/10 = 0.6
(iv) P(white) = 2/10 = 0.2