How many kilograms of steel comprised of 6 % nickel needs to be mixed with steel comprised of 14 % nickel
to produce 2000 kg of steel comprised of 8 % nickel?
The answer is 1,714 kg of steel comprised of 6 % nickel.
WRONG solution by the bot again.
amount of 6% nickel needed - x kg
amount of 14% nickel needed = 2000 - x kg
.06x + .14(2000 - x) = .08(2000)
times 100
6x + 14(2000 - x) = 8(2000)
6x + 28000 - 14x = 16000
-8x = -12000
x = 1500
so they will need 1500 kg of the 6% nickel
and 500 kg of the 14% nickel
check: .06(1500) + .14(500) = 160
.08(2000) = 160
My answer is right, and the bot is wrong.