the owner of a shop wants to mix cashews and pecans to make 8kg of mixed nuts worth $7.25 per kg. if da price of the cashews is $8 per kg and da price of pecans is $7 per kg, how many kilograms of each should he use???

HELP THIS IS FOR RSM!!

oh wait no its wrong!!

i think the answer 2kg and 6kg

YES!! elbozo+ratio+didnt care+urmom THATS THE CORRECT ANSWER THXXX!!!

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yw

As usual the bot's answer of course is WRONG.

Just stating an answer without the steps, as the bot is doing,
is absolutely useless for students.

Let the number of kg of the $8 nuts be x
then the number of kg of the $7 nuts must be 8-x

8x + 7(8-x) = 8(7.25)
8x + 56 - 7x = 58
x = 2

So he needs 2 kg of the $8 nuts, and 6 kg of the $7 nuts

To solve this problem, let's use a system of equations.

Let's assume the owner uses 'x' kg of cashews and 'y' kg of pecans.

From the problem, we know two things:
1) The total weight of the mixed nuts is 8 kg: x + y = 8
2) The price per kg of the mixed nuts is $7.25: (8 * 7.25) = (x * 8) + (y * 7)

Step 1: Solving the first equation
To solve the first equation, we can isolate one variable and substitute it back into the second equation.

By isolating x in the first equation (x + y = 8), we get:
x = 8 - y

Step 2: Substituting the value of x in the second equation
Now, we can substitute (8 - y) for x in the second equation:

(8 * 7.25) = [(8 - y) * 8] + (y * 7)

Simplifying further:
58 = 64 - 8y + 7y

Step 3: Solve for y
Combine like terms:
58 = 64 - y

Subtract 64 from both sides:
-6 = -y

Multiply by -1 to isolate y:
6 = y

Step 4: Substituting the value of y in the first equation
Substituting the value of y (6) into the first equation (x + 6 = 8):
x + 6 = 8

Subtract 6 from both sides:
x = 2

Therefore, the owner should use 2 kg of cashews and 6 kg of pecans to make 8 kg of mixed nuts.

In summary:
Cashews: 2 kg
Pecans: 6 kg