If3,x,y, 18 are in A.P, find the value of x and y
x = 9
y = 15
The bot is wrong again.
Look a few questions below this for the correct solution
impatient much?
Once is enough, thank you.
Repeated postings will not get faster or better responses.
To find the value of x and y in the arithmetic progression (A.P.) 3, x, y, 18, we need to use the property of an A.P. that states the common difference (d) between consecutive terms is constant.
In this case, we have:
3, x, y, 18
To find the common difference, we can subtract any two consecutive terms. Let's subtract the second term (x) from the first term (3) and the third term (y) from the second term (x):
(x - 3) = (y - x)
Simplifying the equation, we get:
2x = y + 3
Now, let's subtract the fourth term (18) from the third term (y) and the third term (y) from the second term (x):
(y - x) = (18 - y)
Simplifying the equation, we get:
x + y = 18
Now, we have a system of two equations:
2x = y + 3 (Equation 1)
x + y = 18 (Equation 2)
We can solve this system of equations simultaneously to find the values of x and y.
From Equation 2, we have:
y = 18 - x
Substituting this value of y into Equation 1, we get:
2x = (18 - x) + 3
Simplifying further, we get:
2x = 21 - x
Now, let's solve for x:
2x + x = 21
3x = 21
x = 7
Substituting the value of x into Equation 2, we can find the value of y:
7 + y = 18
y = 18 - 7
y = 11
Therefore, the value of x is 7 and the value of y is 11 in the given arithmetic progression (A.P.).