A micrometeor has a mass of 0.005 grams. When it enters Earth’s atmosphere, it travels at 21,000 meters per second. What is its kinetic energy when it enters Earth’s atmosphere?
KE=12mv2
(1 point)
Responses
0.0525 J
0.0525 J
1,102,500 J
1,102,500 J
1,102.5 J
1,102.5 J
2,205 J
2,205 J
KE = 1/2 mv^2 = 1.2 * 5*10^-6 * 21000^2 = 1102.5
Well, well, well! Looks like we have a speedy little micrometeor on our hands! To calculate its kinetic energy, we need to use the equation KE = 1/2mv^2.
Now, plugging in the given values, we have:
KE = 1/2 * 0.005 g * (21,000 m/s)^2
And after some calculations, the answer is... drumroll, please... 1,102.5 J! So, it seems like this micrometeor packs quite a punch when it enters Earth's atmosphere. Watch out, world!
To find the kinetic energy of the micrometeor, you can use the formula KE = 1/2 * m * v^2, where KE is the kinetic energy, m is the mass, and v is the velocity.
Plugging in the values given:
KE = 1/2 * 0.005 grams * (21,000 meters per second)^2
First, we need to convert the mass from grams to kilograms:
0.005 grams = 0.005 * 0.001 kilograms = 0.000005 kilograms
Now, we can calculate the kinetic energy:
KE = 1/2 * 0.000005 kilograms * (21,000 meters per second)^2 = 1/2 * 0.000005 * (21,000)^2 = 1/2 * 0.000005 * 441,000,000
Simplifying the expression:
KE = 0.000002205 * 441,000,000 = 970.05 Joules
Therefore, the kinetic energy of the micrometeor when it enters Earth's atmosphere is approximately 970.05 Joules.
To find the kinetic energy (KE) of the micrometeor, we can use the formula KE = 1/2 * mass * (velocity)^2. Given that the mass of the micrometeor is 0.005 grams and its velocity is 21,000 meters per second, we can substitute these values into the formula:
KE = 1/2 * 0.005 grams * (21,000 meters per second)^2
First, let's convert the mass from grams to kilograms by dividing it by 1000:
0.005 grams = 0.005/1000 = 0.000005 kilograms
Now we can substitute the values into the formula:
KE = 1/2 * 0.000005 kilograms * (21,000 meters per second)^2
Next, let's square the velocity:
(21,000 meters per second)^2 = 441,000,000 meters squared per second squared
Now, we can plug this value back into the formula:
KE = 1/2 * 0.000005 kilograms * 441,000,000 meters squared per second squared
Simplifying, we get:
KE = 0.5 * 0.000005 kilograms * 441,000,000 meters squared per second squared
Multiplying the numbers, we have:
KE = 0.000002205 kilograms * 441,000,000 meters squared per second squared
Now, let's simplify the units:
KE = 0.000002205 kilograms * 441,000,000 (m^2/s^2)
Multiplying these values, we get:
KE = 0.000002205 * 441,000,000 (kg * m^2/s^2)
Finally, let's compute the result:
KE = 973.05 kg * m^2/s^2
KE ≈ 973 J
After rounding to the appropriate number of significant figures, the kinetic energy of the micrometeor when it enters Earth's atmosphere is approximately 973 J.
Therefore, the correct answer is
1,102.5 J