What is the force on a 0.0050 C charge in an electric field of 300 V/m?(1 point)
Responses
A. 60,000 N
B. 300.0050 N
C. 1.5 N
D. 1.7 × 10−5 N
D. 1.7 × 10−5 N
To find the force on a charge in an electric field, you can use the formula: Force (F) = charge (q) * electric field (E).
Given:
Charge (q) = 0.0050 C
Electric field (E) = 300 V/m
Plug in the given values into the formula:
F = 0.0050 C * 300 V/m
Multiply the values:
F = 0.0015 N
Therefore, the force on the 0.0050 C charge in an electric field of 300 V/m is 0.0015 N.
The correct option is C. 1.5 N.
To calculate the force on a charge in an electric field, you can use the equation:
Force (F) = charge (q) × electric field (E)
Given:
Charge (q) = 0.0050 C
Electric field (E) = 300 V/m
Plugging in the values:
F = 0.0050 C × 300 V/m
F = 1.5 N
Therefore, the correct answer is C. 1.5 N.