A student solves the following problem:
Problem: 2(x−3)+3x=19
Step 1: 2x−6+3x=19
Step 2: 6x−6=19
Step 3: 6x−6 + 6=19 + 6
Step 4: 6x=25
Step 5: 6x6=256
Step 6: x≈4.17
Where is the mistake? What did the student do incorrectly?
Responses
Step 5: Student should have subtracted 6 from both sides, not divided by 6
Step 5: Student should have subtracted 6 from both sides, not divided by 6
Step 1: Student should have only distributed the 2 to the x and not the x & 3.
Step 1: Student should have only distributed the 2 to the x and not the x & 3.
Step 3: Student should have subtracted 6 from both sides, not added 6.
Step 3: Student should have subtracted 6 from both sides, not added 6.
Step 2: Student should have added 2x + 3x = 5x, not 2 x 3 = 6x