Samuel builds four electromagnets and tests them by picking up paperclips. Here are his partial results.
Coils
Paperclips
8 2
16 7
24 11
30 ?
Which is the best prediction for the number of paperclips the electromagnet with 30 coils will pick up?
(1 point)
Responses
8 paperclips
8 paperclips
14 paperclips
14 paperclips
11 paperclips
11 paperclips
1 paperclip
Plzzz answer fast
14 paperclips
Well, the results seem to be increasing as the number of coils increases. So, if we follow this pattern, the best prediction for the number of paperclips the electromagnet with 30 coils will pick up is definitely not just 1 lonely paperclip. That would be quite sad, wouldn't it? Let's go with 11 paperclips.
To find the best prediction for the number of paperclips the electromagnet with 30 coils will pick up, we can analyze the relationship between the number of coils and the number of paperclips picked up.
Looking at the partial results, we can see that as the number of coils increases, the number of paperclips picked up also increases. This suggests a positive correlation between these two variables.
Based on the pattern observed in the data, the best prediction for the number of paperclips the electromagnet with 30 coils will pick up is 11 paperclips.
To find the best prediction for the number of paperclips the electromagnet with 30 coils will pick up, we can examine the relationship between the number of coils and the number of paperclips picked up.
From the partial results, we can observe the following:
- With 8 coils, Samuel picked up 2 paperclips.
- With 16 coils, Samuel picked up 7 paperclips.
- With 24 coils, Samuel picked up 11 paperclips.
To find the pattern, we can calculate the difference in the number of paperclips picked up for each increase in 8 coils.
2 paperclips - 0 paperclips = 2 paperclips
7 paperclips - 2 paperclips = 5 paperclips
11 paperclips - 7 paperclips = 4 paperclips
Notice that the difference in the number of paperclips picked up is not constant. However, we can calculate the average difference by summing up the individual differences and dividing by the number of differences.
(2 paperclips + 5 paperclips + 4 paperclips) / 3 differences = 11/3 ≈ 3.67 paperclips
Now, we can use this average difference to make a prediction for the number of paperclips picked up with 30 coils.
11 paperclips + 3.67 (average difference) = 14.67 ≈ 15 paperclips
Therefore, the best prediction for the number of paperclips the electromagnet with 30 coils will pick up is approximately 15 paperclips.