a flashlight has four 1.5-volt batteries the bulb has a resistance of 2.4 ohms. what is the amerage of the curcuit
2.5 a
0.4a
0.625a
14.4 a
To calculate the amperage of the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R).
In this case, the voltage (V) is the total voltage of the four 1.5-volt batteries, which is 4 x 1.5 = 6 volts. The resistance (R) is given as 2.4 ohms.
Using Ohm's Law, we can calculate the amperage (I) as:
I = V / R
I = 6 / 2.4
I ≈ 2.5 amps
Therefore, the correct answer is 2.5 A.