Hihi i need help again.
Question 1. Using your equation, what is the population after 10 years?
P = 6791 - 15y
y = years (15)
p = population (6791)
Question 2.
Using your equation, what fee did the technician earn after working 1.25 hours?
C = 75 + 35h
h = hours (35)
c = charge (75)
Thanks
for your help!
Answer 1: The population after 10 years is 4791.
Answer 2: The technician earned a fee of $106.25 after working 1.25 hours.
Wrong again
a) 6791 - 150 = 6641 , not 4791
b) 75 + 35(1.25) = 118.75 ,not 106.25
ok thanks-
Hello! I'd be happy to help you with your questions.
Question 1: To find the population after 10 years using the equation P = 6791 - 15y, you need to substitute the value of y (years) with 10 and solve for P (population).
So, you have:
P = 6791 - 15 * 10
P = 6791 - 150
P = 6641
Therefore, the population after 10 years is 6,641.
Question 2: To find the fee the technician earned after working 1.25 hours using the equation C = 75 + 35h, you need to substitute the value of h (hours) with 1.25 and solve for C (charge).
So, you have:
C = 75 + 35 * 1.25
C = 75 + 43.75
C = 118.75
Therefore, the technician earned a fee of 118.75 dollars after working 1.25 hours.
I hope this helps! Let me know if you have any further questions.