Graph a right triangle with the two points forming the hypotenuse. Using the sides, find the distance between the two points, to the nearest tenth (if necessary).
(3, 6) \text{ and } (-6, -6)
(3,6) and (−6,−6)
AAAaannndd the bot gets it wrong yet again!
the distance is √((6+3)^2 + (6+6)^2) = √(9^2 + 12^2) = 15
The graph of the right triangle is shown below:
\begin{tikzpicture}
\draw[->] (-7,0) -- (7,0) node[right] {$x$};
\draw[->] (0,-7) -- (0,7) node[above] {$y$};
\draw (3,6) -- (-6,-6) -- (3,6);
\draw[fill] (3,6) circle [radius=2pt];
\draw[fill] (-6,-6) circle [radius=2pt];
\end{tikzpicture}
The distance between the two points is 9.0.