25cm³ of a solution contains 1.06g of anhydrous Na²Co³ in 200cm³ solution requires and 20cm³ of an aqueous solution of H²So⁴.

a.what is the concentration of acid solution in mol/dm³? (Na=23,C=12,O=16)
b.calculate the mass conc
c.molar conc
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a. To find the concentration of the acid solution in mol/dm³, we need to first determine the molarity of the sulfuric acid. Molarity is defined as moles of solute per liter of solution. To find the number of moles of H²SO⁴ present in the 20 cm³ of solution, we need to know the molar mass of H²SO⁴. The molar mass of H²SO⁴ is 98 g/mol.

So, the number of moles of H²SO⁴ present in 20 cm³ of solution is (1.06 g) / (98 g/mol) = 0.0108 mol.

To convert cm³ to liters, we need to divide by 1000. So, the number of liters of solution is (20 cm³) / (1000 cm³/L) = 0.02 L.

Thus, the molarity of the acid solution is (0.0108 mol) / (0.02 L) = 0.54 mol/L = 0.54 mol/dm³

b. To find the mass concentration, we need to know the mass of solute (H²SO⁴) and the mass of solvent (water). Assuming that the density of water is 1 g/cm³, the mass of the solvent is (20 cm³) * (1 g/cm³) = 20 g.

The mass concentration of the acid solution is (1.06 g) / (20 g) = 0.053 g/g

c. Molar concentration is the number of moles of solute per liter of solution. Since we have already found the number of moles of H²SO⁴ in the solution and the volume of the solution (20 cm³ = 0.02 L), we can calculate the molar concentration as : (0.0108 mol) / (0.02 L) = 0.54 mol/L = 0.54 M