Login or Sign Up

Ask a New Question

Questions
Math

C = 280 - F

1.2C + 1.15F = 1.2(280-F) + 1.15F = 328

Solve for F, then C.

1 answer
asked anonymously
1 year ago
56 views
1. 0
2. 0

F = 48

C = 232

answered by Bot
1 year ago
1. 0
2. 1

You can ask a new question or answer this question.

Did you know?

Did you know that the equation C = 280 - F is used to relate the temperatures in Celsius (C) and Fahrenheit (F)? This equation allows you to convert a temperature from Fahrenheit to Celsius and vice versa. Additionally, did you know that the equation 1.2C + 1.15F = 328 can be used to find the corresponding values of F and C? By solving this equation, you can determine the specific values of both F and C when converting between Fahrenheit and Celsius temperatures.

Related Questions

Silvio's gross earnings for last week were $328.54. His remuneration consists of a base salary of $280 plus a commission
Hi I really need help with this problem, thanks.Divide (20x^2-12x+8)/(2x+8) these are the choices: A. 10x-34+ 280/2x-8 B.
What is the volume of a cone with a diameter of 20 cm and a height of 15 cm? (1 point)Responses 2,355 cubic centimeters 2,355
350 is 70% of what number?A) 500 B) 420 C) 245 D) 280 What percent of 64 is 24? A) 267% B) 62.5% C) 40% D) 37.5% What percent of
Solve for the surface area of the triangular prism.(1 point) Responses 180 square centimeters 180 square centimeters 280 square
You made $280.00 for working 40 hours, which is described by 40y=$280.00x . Determine your earnings per hour.
350 is 70% of what number?A) 500 *** B) 420 C) 245 D) 280 What percent of 64 is 24? A) 267% B) 62.5% C) 40% D) 37.5% *** What
you made $280.00 for working 40 hours which is described by 40y = $280.00x determine your earning per hour
Surface Area of Triangular Prisms Quick Check3 of 53 of 5 Items Question Use the image to answer the question. Solve for the
Solve for the surface area of the triangular prism. (1 point) Responses 260 square centimeters 260 square centimeters 280 square

Questions LLC

Use AI to answer your questions.

Ask a New Question

Company

About Us
Careers
Contact Us
Privacy Policy
Terms of Use

Questions

Archives
Categories
Newest
Random
Search

Trending

Now
Today
Week
Month
Year

Social

Facebook
Instagram
LinkedIn
YouTube
X

© 2024 Questions LLC. All rights reserved.