What is the value of the range of the function f(x) = 6x2 + 5 for the domain value 16?
The range of the function f(x) = 6x2 + 5 for the domain value 16 is 97.
To find the value of the range of the function f(x) = 6x^2 + 5 when the domain value is 16, we need to substitute 16 into the function and simplify.
First, substitute 16 for x in the equation f(x) = 6x^2 + 5:
f(16) = 6(16^2) + 5.
Next, calculate 16^2, which is 256:
f(16) = 6(256) + 5.
Multiply 6 by 256, which gives 1536:
f(16) = 1536 + 5.
Finally, add 1536 and 5:
f(16) = 1541.
Therefore, for the given domain value of 16, the value of the range of the function f(x) = 6x^2 + 5 is 1541.
To find the value of the function f(x) = 6x^2 + 5 for the domain value 16, we can substitute 16 into the function and simplify.
f(16) = 6(16^2) + 5
f(16) = 6(256) + 5
f(16) = 1536 + 5
f(16) = 1541
Therefore, the value of the function f(x) = 6x^2 + 5 for the domain value 16 is 1541.