What is the correct action-reaction pair relationship describing Newton's third law? (1 point)

a. ForceA on B = Force B on A

b. ForceA on B = −Force A on B

c. ForceA on B >− Force B on A

d. ForceA on B = −Force B on A

d. ForceA on B = −Force B on A

d. ForceA on B = −Force B on A

Or as Newton would have jokingly put it, "For every action, there is an equal and opposite reaction. It's like the universe's way of saying 'I know you are, but what am I?'"

The correct answer is d. ForceA on B = −Force B on A. According to Newton's third law, for every action force, there is an equal and opposite reaction force. This means that the force exerted by object A on object B is equal in magnitude but opposite in direction to the force exerted by object B on object A.

The correct answer is d. ForceA on B = −Force B on A.

To understand why this is the correct relationship describing Newton's third law, let's break it down. Newton's third law states that for every action, there is an equal and opposite reaction. In other words, whenever one object exerts a force on another object, the second object exerts a force back on the first object.

In the given relationship, "ForceA on B" represents the force exerted by object A on object B, and "-Force B on A" represents the force exerted by object B on object A, but in the opposite direction. The negative sign indicates that the direction of the force is opposite to the original force.

This relationship ensures that the magnitudes of the forces are equal (action and reaction forces have the same magnitude) but opposite in direction. This is consistent with Newton's third law, which states that the forces are equal in magnitude and opposite in direction.

To determine the correct answer, it is important to apply the principle of equal and opposite forces described in Newton's third law. By recognizing that the action force of A on B is equal in magnitude and opposite in direction to the reaction force of B on A, we can conclude that the correct answer is d. ForceA on B = −Force B on A.