How many gallons of rocket fuel containing 80% liquid oxygen must be mixed with 250 gallons containing 40% liquid oxygen to produce a mixture containing 70% liquid oxygen?
Of course the canned answer by the "robot answer generator"
is wrong again.
Besides, just stating the answer without a solution is useless
number of gallons of 80% mixture to be added ---- x
.8x + .4(250) = .7(x + 250)
times 10
8x + 4(250) = 7(x + 250)
8x + 1000 = 7x + 1750
x = 750 <----- number of gallons of 80% mixture
wrong again, as usual.
80x + 40*250 = 70(x+250)
x=750
To find the number of gallons of rocket fuel containing 80% liquid oxygen that must be mixed with 250 gallons containing 40% liquid oxygen to produce a mixture containing 70% liquid oxygen, we can use a basic equation.
Let's assume x represents the number of gallons of rocket fuel with 80% liquid oxygen required.
To solve this question, follow these steps:
Step 1: Identify the given information:
- Liquid oxygen concentration in the rocket fuel = 80%
- Liquid oxygen concentration in the 250 gallons mixture = 40%
- Liquid oxygen concentration desired in the final mixture = 70%
Step 2: Set up the equation based on the information above:
The equation can be set up using the concept of the amount of liquid oxygen in each mixture, which remains the same during the mixing process.
The amount of liquid oxygen in the mixture of rocket fuel with 80% concentration = x gallons * 0.8
The amount of liquid oxygen in the 250 gallons mixture with 40% concentration = 250 gallons * 0.4
The amount of liquid oxygen in the final mixture with 70% concentration = (x + 250) gallons * 0.7
Since the amount of liquid oxygen is constant, we can equate these amounts:
x * 0.8 + 250 * 0.4 = (x + 250) * 0.7
Step 3: Solve the equation for x:
0.8x + 100 = 0.7x + 175
0.8x - 0.7x = 175 - 100
0.1x = 75
x = 75 / 0.1
x = 750
Therefore, 750 gallons of rocket fuel containing 80% liquid oxygen must be mixed with 250 gallons containing 40% liquid oxygen to produce a mixture containing 70% liquid oxygen.