Suppose a 63-kg boy and a 44-kg girl use a massless rope in a tug-of-war on an icy, resistance-free surface. If the acceleration of the girl toward the boy is 3.0 m/s2, find the magnitude of the acceleration of the boy toward the girl.
Close, just switch some numbers around.
The magnitude of the acceleration of the boy toward the girl is 4.5 m/s2.
This can be calculated using Newton's Second Law of Motion:
F = ma
F = (63 kg)(3.0 m/s2) - (44 kg)(a)
a = 4.5 m/s2