A tow truck tows a 1550 kg, starts a text, space, k, g, end text car along a level road. The cable attaching the car to the tow truck makes an angle of 37, degrees above the horizontal. The coefficient of friction between the car and the road is 198=0.198mu, equals, 0, point, 198, and the tension in the cable is 6510 N, start a text, space, N, end text.
To find the force of friction between the car and the road, we need to use the coefficient of friction and the normal force acting on the car.
First, let's find the normal force. The normal force is equal to the weight of the car since the car is on a level road. The weight is calculated by multiplying the mass of the car by the acceleration due to gravity:
Weight = mass * gravitational acceleration
Weight = 1550 kg * 9.8 m/s^2
Weight = 15190 N
Next, we can calculate the force of friction. The force of friction can be found by multiplying the coefficient of friction (mu) by the normal force.
Force of friction = coefficient of friction * normal force
Force of friction = 0.198 * 15190 N
Force of friction = 3000.42 N
Therefore, the force of friction between the car and the road is approximately 3000.42 N.