Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from 𝑛=4 to 𝑛=1.
energy emitted: ______ J
delta E = 2.18E-18 (1/(n1)2 - 1/(n2)2
delta E = 2.18E-18 (1/1^2 - 1/4^2) Joules = 2.18E-18 (1/1 - 1/16) Joules
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