Given that 231n-143n=44n
assuming that n is the base in your number system
and you are finding n ....
2n^2 + 3n + 1 - (n^2 + 4n + 3) = 4n + 4
n^2 - 5n - 6 = 0
(n - 6)(n + 1) = 0
n = 6 or -1, but usually the base is a whole number
n = 6
and you are finding n ....
2n^2 + 3n + 1 - (n^2 + 4n + 3) = 4n + 4
n^2 - 5n - 6 = 0
(n - 6)(n + 1) = 0
n = 6 or -1, but usually the base is a whole number
n = 6