Question

L varies partly lnversely as m and is partly, constant when l =3, m=2 and when l=9,m=5.find m when l = 1

Answer 1

l = a/m + b

a/2 + b = 3
a/5 + b = 9
subtract to get
3a/10 = -6
a -20
so now you have
l = -20/m + 13
so when l=1,
-20/m + 13 = 1
m = 5/3