1. lx +5=18 (I point)
05or-5
013or-13
0180r-18
023or-23
2. y+4 <1 (1 point)
0-5 <y<-3
0-3<4<5
0-4<y<1
O1<y<4
3. 12t1 - 5=7 (1 point)
Ot=1or-1
Ot=60r-6
O+=10 or-10
O+=12or-12
A.
3
lal.
1
0
0
5
(1 point)
8
1
§
O
O
O
or
-1
O| W
To solve these equations, you need to isolate the variable on one side of the equation. Here's how you can solve each equation:
1. lx + 5 = 18
To isolate x, subtract 5 from both sides of the equation:
lx + 5 - 5 = 18 - 5
lx = 13
This simplifies to lx = 13.
Now, divide both sides of the equation by l to solve for x:
x = 13/l
Therefore, the solution to the equation is x = 13/l. Since l can be any non-zero number, the answer can be expressed as x = 13/l where l ≠ 0.
2. y + 4 < 1
To isolate y, subtract 4 from both sides of the inequality:
y + 4 - 4 < 1 - 4
y < -3
Therefore, the solution to the inequality is y < -3.
3. 12t1 - 5 = 7
To isolate t, add 5 to both sides of the equation:
12t1 - 5 + 5 = 7 + 5
12t1 = 12
Divide both sides of the equation by 12 to solve for t:
t1 = 12/12
t1 = 1
Therefore, the solution to the equation is t1 = 1.
As for the last response you provided, it seems to be unrelated to the given equations. If you have any more questions or need further assistance, please let me know.