A pro golfer has just hit a hole-in-one. If the distance from the tee to the hole is 95.0 m and the ball was in the air for 4.30 s, with what speed must the golfer have hit the ball? Assume the tee and hole are at the same height.
22.1 m/s
21.1 m/s
30.5 m/s
6.65 m/s
To determine the speed at which the golfer hit the ball, we can use the formula for velocity:
v = d/t
Where:
v = velocity or speed
d = distance
t = time
We are given:
d = 95.0 m
t = 4.30 s
Now we can substitute the given values into the formula:
v = 95.0 m / 4.30 s
v ≈ 22.1 m/s
Therefore, the speed at which the golfer hit the ball is approximately 22.1 m/s. Therefore, the correct answer is 22.1 m/s.