The melting point of indium is 156.2°C. At 323°F, what is the physical state of indium?
323 F = 161.667 C.
It melts @ 156.2 from solid to liquid; therefore @ 161.667 it is a liquid if it hasn't reached the boiling point. I look up the boiling point and found it to be over 2000 C.
Ah, indium, always in a state of identity crisis! At 323°F, you'll find indium shaking things up and being in its liquid state. It's like it just can't make up its mind! Slightly rebellious, wouldn't you say?
To determine the physical state of indium at 323°F, we first need to convert 323°F to Celsius. To convert Fahrenheit to Celsius, we can use the following formula:
°C = (°F - 32) / 1.8
Let's calculate the temperature in Celsius:
°C = (323 - 32) / 1.8
= 291 / 1.8
≈ 161.67°C
Comparing the calculated temperature of approximately 161.67°C to the melting point of indium, which is 156.2°C, we can determine the physical state of indium.
Since the temperature is greater than the melting point, which indicates that the temperature is higher than the melting point of indium, the physical state of indium at 323°F (approximately 161.67°C) would be a liquid.
To determine the physical state of indium at 323°F, we need to convert the temperature from Fahrenheit to Celsius since the melting point of indium is given in Celsius.
The formula to convert Fahrenheit to Celsius is:
°C = (°F - 32) * 5/9
Let's do the conversion:
°C = (323 - 32) * 5/9
°C = 291 * 5/9
°C ≈ 160.56
Since the melting point of indium is 156.2°C, which is lower than the converted temperature of 160.56°C, we can conclude that at 323°F, indium would be in its liquid state.