A spelunker (cave explorer) drops a stone from rest into a hole. The speed of sound is 343 m/s in air, and the sound of the stone striking the bottom is heard 5.89 s after the stone is dropped. How deep is the hole?
if the distance is x, then
x = 4.9t^2
so t = √(x/4.9) to fall
the round trip then means
√(x/4.9) + x/343 = 5.89
x = 146.27 meters