Find the area of the region enclosed by the curves y=x3−2x2 and y=2x2−3x.
x^3-2x^2 = 2x^2 - 3x intersect at x=0,1,3
If you want the geometric area, that would be
∫[0,3] |(x^3-2x^2) - (2x^2 - 3x)| dx = 37/12
If you want the geometric area, that would be
∫[0,3] |(x^3-2x^2) - (2x^2 - 3x)| dx = 37/12