2 cells each of emf 2volts and resistance 0.5 ohms are connected in series.they are made to supply current to a combination of 3 resistor, one of the resistance 2ohms is connected in series to a parallel combination of two other resistor each of resistance 3ohms .draw a circuit diagram

Calculate the current in the circuit
Combination of the potential difference across the parallel resistor
Lost volts of the battery

the total R = 0.5 + 0.5 + 2 + 1/(1/3 + 1/3) = 4.5 Ω

current = 4/4.5 = ____ V
see what you can do with the rest