Given that x2+y2=5xy, show that log(x-y/√3)=1/2(logx+logy)
x^2 + y^2 = 5xy
x^2 - 2xy + y^2 = 5xy - 2xy
(x-y)^2 = 3xy
(x-y)^2/3 = xy
Now finish it off. Post your work if you get stuck
x^2 - 2xy + y^2 = 5xy - 2xy
(x-y)^2 = 3xy
(x-y)^2/3 = xy
Now finish it off. Post your work if you get stuck