find a logistic function that satisfies these conditions:
initial value = 10
limit to growth = 40
passes through (1,20)
Given the first two restrictions, we have
f(x) = 40/(1 + e^(-k(x-10))
so now, using f(1)=20 find the value of k.
initial value = 10
limit to growth = 40
passes through (1,20)
f(x) = 40/(1 + e^(-k(x-10))
so now, using f(1)=20 find the value of k.