A uniform metre of mass 150g is pivoted freely at the 0cm mark. What force applied vertically upwards at the 60cm mark is needed to maintain the rule horizontaly?
center of mass is at 50 cm
.150 kg * g * 50 cm = f * 60 cm ... f is in Newtons
.150 kg * g * 50 cm = f * 60 cm ... f is in Newtons