so if a(t) = 12t+3 v(t) = 6t^2 + 3t + c given: v(2) = 9 ---> 9 = 6(2)^2 + 3(2) + c c = -21 so v(t) = 6t^2 + 3t - 21 s(t) = 2t^3 + (3/2)t^2 - 21t + k given: s(1) = -2 ----> -2 = 2(1) + 3/2 - 21 + k k = 31/2 s(t) = 2t^3 + (3/2)t^2 - 21t + 31/2
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