A box with a mass of 10kg rests on a frictionless surface which makes an angle of 30o with the horizontal. How large a force must be applied to the box, parallel to the incline to hold the box stationary on the incline
answers please
well, the force along the plane is mg sinθ
so ...
To find the force needed to hold the box stationary on the incline, you can use the concept of forces and Newton's second law of motion.
First, you need to find the component of the gravitational force acting along the incline. This can be done using the formula:
Force along incline (F_g_parallel) = mass (m) * gravity (g) * sin(theta)
where:
m = mass of the box (10 kg)
g = acceleration due to gravity (9.8 m/s^2)
theta = angle of incline (30 degrees)
Plugging in the values:
F_g_parallel = 10 kg * 9.8 m/s^2 * sin(30 degrees)
Next, since the box is stationary and there is no acceleration, the force needed to hold it in place must exactly balance the force pulling it down the incline. Therefore, the force needed to hold the box stationary on the incline is equal to the component of the gravitational force acting along the incline:
Force needed (F_needed) = Force along incline (F_g_parallel)
Calculating the values:
F_needed = 10 kg * 9.8 m/s^2 * sin(30 degrees)
Now, you can solve this equation to find the force required to hold the box in place on the incline.