An arrow is shot into the air with an initial velocity of 100m/s at an elevation of 60 degree find,the time of flight, the maximum height attained, the range
first vertical problem
Vinitial up = Vi = 100 sin 60
v = Vi - g t = 100 sin 60 - 9.81 t = 86.6 - 9.81 t
v = 0 at top
so at top
9.81t = 86.6
t = 8.83 seconds going up (so time of flight = 2 * 8.83 = 17.7 seconds)
h = 0 + Vi t - 4.9 t^2 = 86.6 (8.83)- 4.9 (8.83)^2
range = 100 cos 60 * 17.7