A 5kg mass on horizontal platform accelerated at the rate of 0.1m/s^2 when a horizontal force of 10newton is applied to it .Caculate the co-efficient between it and the platform(g=10m/s^2).
friction force = 5 * 10 * mu = 50 mu Newtons
net force = 10 - 50 mu Newtons
F = m a
10 -50 mu = 5 * 0.1 = 0.5
50 mu = 9.5
mu = 9.5 /50
To calculate the coefficient of friction between the mass and the platform, we can use the equation:
Coefficient of friction (μ) = (Force of friction / Normal force)
First, we need to find the force of friction. The force of friction can be calculated using Newton's second law of motion:
Force of friction = mass × acceleration
Given:
Mass (m) = 5 kg
Acceleration (a) = 0.1 m/s^2
Force of friction = 5 kg × 0.1 m/s^2
Force of friction = 0.5 N
Now, let's calculate the normal force. The normal force is the force exerted by the platform on the mass, which is equal to the weight of the mass.
Weight = mass × acceleration due to gravity
Given:
Mass (m) = 5 kg
Acceleration due to gravity (g) = 10 m/s^2
Weight = 5 kg × 10 m/s^2
Weight = 50 N
Since the mass is on a horizontal platform, the normal force is equal to the weight (since there is no vertical motion or acceleration).
Normal force = 50 N
Now, we can calculate the coefficient of friction:
Coefficient of friction (μ) = (Force of friction / Normal force)
Coefficient of friction (μ) = 0.5 N / 50 N
Coefficient of friction (μ) = 0.01
Therefore, the coefficient of friction between the mass and the platform is 0.01.
To calculate the coefficient of friction between the mass and the platform, we need to first identify the forces acting on the mass.
Given:
Mass of the object (m) = 5 kg
Acceleration (a) = 0.1 m/s^2
Applied force (F) = 10 N
Acceleration due to gravity (g) = 10 m/s^2
The forces acting on the mass are:
1. The applied force in the direction of acceleration (F).
2. The force of gravity acting downwards (mg).
The net force on the mass can be calculated using Newton's second law:
Net force (Fnet) = ma
Since the mass is accelerating in the positive direction, the net force can be written as:
Fnet = F - mg
Applying Newton's second law, we have:
ma = F - mg
Substituting the given values, we get:
5 kg * 0.1 m/s^2 = 10 N - (5 kg * 10 m/s^2)
Now, let's solve for the coefficient of friction:
F - mg = 0.5 N (simplifying the left side)
10 N - (5 kg * 10 m/s^2) = 0.5 N
Simplifying further:
10 N - 50 N = 0.5 N
-40 N = 0.5 N
Rearranging the equation, we get:
0.5 N + 40 N = 0
40.5 N = 0
Since the forces on the left and right sides of the equation are not equal, this implies that an error has occurred in the calculations. Please recheck the values provided or the calculations performed.