A positive of charge q1=0.36 C is placed 12 m west of another positive charge q2=0.49C. A third negative charge q3= -0.25 C is placed 5.0 m north of q2. What is the net electric force on q2?
Well, well, well, it seems we have a charge party going on! Let's calculate the net electric force on q2, shall we?
First, we need to calculate the magnitude of the electric force between q1 and q2. We can use Coulomb's law for this, which states that the force is equal to k times the product of the charges divided by the square of the distance between them:
F1-2 = k * |q1| * |q2| / r1-2^2
Plugging in the values, we get:
F1-2 = k * |0.36 C| * |0.49 C| / (12 m)^2
Now, let's calculate the magnitude of the electric force between q2 and q3. Using the same formula:
F2-3 = k * |q2| * |q3| / r2-3^2
Plugging in the values once again:
F2-3 = k * |0.49 C| * |-0.25 C| / (5.0 m)^2
Now, since q1 and q2 are positive charges while q3 is negative, the forces F1-2 and F2-3 will have opposite directions. So, let's subtract the forces:
Fnet = F1-2 - F2-3
But be careful! Forces are vector quantities, meaning they have both magnitude and direction. So, make sure to include those directions in your calculations.
I hope I gave you a bit of charge humor while explaining this electric situation. In any case, I hope this helps you solve the problem!
To find the net electric force on charge q2, we need to calculate the individual forces between q2 and q1, as well as q2 and q3, and then add them together.
The electric force between two charges is given by Coulomb's Law:
F = (k * |q1 * q2|) / r^2
where F is the electric force, k is Coulomb's constant (9.0 x 10^9 Nm^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.
First, let's calculate the force between q1 and q2:
Distance between q1 and q2 is 12 m.
Charge q1 = 0.36 C
Charge q2 = 0.49 C
Plugging these values into Coulomb's Law:
F1 = (9.0 x 10^9 Nm^2/C^2 * |0.36 C * 0.49 C|) / (12 m)^2
Calculating F1:
F1 = (9.0 x 10^9 Nm^2/C^2 * 0.1764 C^2) / 144 m^2
F1 = 12.6 N (rounded to one decimal place)
Now let's calculate the force between q2 and q3:
Distance between q2 and q3 is 5.0 m.
Charge q2 = 0.49 C
Charge q3 = -0.25 C
Plugging these values into Coulomb's Law:
F2 = (9.0 x 10^9 Nm^2/C^2 * |0.49 C * -0.25 C|) / (5.0 m)^2
Calculating F2:
F2 = (9.0 x 10^9 Nm^2/C^2 * 0.1225 C^2) / 25 m^2
F2 = -0.44 N (rounded to two decimal places)
Since q3 is negative, the force between q2 and q3 is attractive, hence the negative sign.
Finally, let's find the net electric force on q2 by summing up the individual forces:
Net force = F1 + F2
Net force = 12.6 N + (-0.44 N)
Net force = 12.2 N (rounded to one decimal place)
Therefore, the net electric force on q2 is 12.2 N.
To find the net electric force on q2, we need to calculate the electric forces between q2 and q1 as well as q2 and q3, and then add them together.
1. Calculate the electric force between q2 and q1:
The electric force between two charges q1 and q2 is given by Coulomb's law:
F = k * |q1 * q2| / r^2
where k is the electrostatic constant (k = 9.0 x 10^9 N m^2 / C^2), q1 and q2 are the charges, and r is the distance between them.
F1 = (9.0 x 10^9 N m^2 / C^2) * |0.36 C * 0.49 C| / (12 m)^2
2. Calculate the electric force between q2 and q3:
F = k * |q2 * q3| / r^2
F2 = (9.0 x 10^9 N m^2 / C^2) * (0.49 C * (-0.25 C)) / (5.0 m)^2
3. Add the electric forces together to find the net force on q2:
Net force = F1 + F2
Net force = F1 + F2
Note: Since q1 and q2 are both positive charges, their electric force on each other is repulsive, and since q3 is a negative charge, the electric force on q3 will be attractive.
Now we can calculate the values to find the net electric force.