A pease of brass of mass 170kg has its temperature raised from 0c to 30c calculate the increase in volume given the density of brass at 0 as 8.5*10 andit cubic expansivity as 5.7*10
To calculate the increase in volume, we need to use the formula for the coefficient of volume expansion:
ΔV = V₀ * β * ΔT
Where:
ΔV is the change in volume
V₀ is the initial volume
β is the coefficient of volume expansion
ΔT is the change in temperature
First, let's find the initial volume, V₀. We can use the density and mass of the brass:
Density (ρ) = mass (m) / volume (V)
Since we know the density (8.5*10^-3 kg/m^3) and mass (170 kg), we can rearrange the formula to solve for volume:
V₀ = m / ρ
V₀ = 170 kg / (8.5*10^-3 kg/m^3)
V₀ = 20,000 m^3
Now, let's calculate the change in volume, ΔV:
ΔT = (30 - 0) °C = 30 °C (temperature change)
β = 5.7*10^-5 / °C (coefficient of volume expansion)
ΔV = V₀ * β * ΔT
ΔV = 20,000 m^3 * 5.7*10^-5 / °C * 30 °C
Calculating this expression will give you the increase in volume (ΔV) of the brass when the temperature is raised from 0°C to 30°C.