The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a consonant both times if the spinner is spun twice.
There are 3 equal parts with the letters E, U, and N
1/9
1/3**
5/9
3/4
Since 3 is an odd number and there are 2 vowels I believe the chances on landing on N is 1/3 due to 2 of the parts being vowels
3 - 2- 1
3 parts
1/3
You are spinning it twice. The spinner has no "memory" of what happened
the first spin as you spin it a second time.
Prob(consonant, then consonant) = (1/3)(1/3) = 1/9
I will attempt to show the tree, difficult in this format
---------------------------------------- start -----------------------------------
---------------------- E --------------------------- U -------------------N ----------------------
EE-----------EU ----------EN ... --UE--------UU---- UN ...-- NE-----NU-------NN
notice there are 9 outcomes, only one, the NN, has both consonants.
so the prob(your event) = 1/9
Thank you!
@mathhelper!
To find the probability that the spinner will land on a consonant both times if the spinner is spun twice, we can use a tree diagram.
First, let's label the branches of the tree diagram with the possible outcomes for the first spin: E, U, and N.
E
/ | \
/ | \
E U N
We then label the branches for the second spin with the possible outcomes for each of the first spin outcomes: E, U, and N.
E
/ | \
/ | \
E U N
/ | \
/ | \
E U N
Since the spinner is divided into 3 equal parts and only one of those parts has a consonant (N), the probability of landing on a consonant on the first spin is 1/3.
For the second spin, the probability of again landing on a consonant (N) is also 1/3, since the spinner is spun independently each time.
To find the probability of both events happening, we multiply the probabilities of each individual event. So, the probability of landing on a consonant both times is (1/3) * (1/3) = 1/9.
Therefore, the correct answer is 1/9.
To find the probability that the spinner will land on a consonant both times, we can use a tree diagram.
First, let's list the options for the first spin: E, U, N.
For each of these options, we can list the options for the second spin: E, U, N.
The tree diagram would look like this:
E U N
/ \ / \ / \
E U E U E U
/ \ / \ / \
E U E U E U
Now, we need to identify the outcomes where the spinner lands on a consonant both times. From the tree diagram, we can see that the outcomes are: EN, EU, UE, UN.
Since there are 9 equally likely outcomes in total (3 options for the first spin multiplied by 3 options for the second spin), and there are 4 favorable outcomes (EN, EU, UE, UN), the probability that the spinner will land on a consonant both times is 4/9.
Therefore, the correct answer is 4/9.