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A girl throws a ball of 0,2 kg mass vertically upwards with an initial velocity of 12 metres per second

Calculate the maximum height reached by the ball above the girls hand

v^2 = 2as, so

12^2 = 2*9.81 s
s = 144/19.62

you can do this using the usual
v = 12-gt = 0
and then using that value of t in
s = 1/2 gt^2

Did you know?

Did you know that you can calculate the maximum height reached by a ball thrown vertically upwards? In a scenario where a girl throws a ball of 0.2 kg mass with an initial velocity of 12 meters per second, the maximum height can be determined using kinematic equations and the laws of physics. By considering the acceleration due to gravity (-9.8 m/s²), you can utilize the equation: v² = u² + 2as where "v" represents the final velocity (which becomes 0 when the ball reaches its maximum height), "u" denotes the initial velocity (12 m/s), "a" indicates acceleration (-9.8 m/s²), and "s" represents the displacement or height. Rearranging this equation, you can solve for "s" and find the maximum height reached by the ball above the girl's hand.