A body mass 6kg moving with a speed of 3m/s is acted on by a force of 18N For 4s. Find the speed of the body
Pls solve it
F = ma, so a = 18/6 = 3
You don't say whether the force is acting with its motion or against it, so I'll just say
v = 3 + at = 3 ± 4*3
so decide which, and either add or subtract the 12 m/s
To find the final speed of the body, we can use the equation:
v = u + at
Where:
v = final velocity (speed)
u = initial velocity (speed)
a = acceleration
t = time
From the given information:
Initial speed (u) = 3 m/s
Mass (m) = 6 kg
Force (F) = 18 N
Time (t) = 4 s
First, let's find the acceleration using Newton's second law of motion:
F = ma
Rearranging the equation, we have:
a = F/m
Now substituting the given values:
a = 18 N / 6 kg
a = 3 m/s²
Now we can substitute the values of initial speed (u), acceleration (a), and time (t) into the first equation to find the final speed (v):
v = u + at
v = 3 m/s + (3 m/s² * 4 s)
v = 3 m/s + 12 m/s
v = 15 m/s
Therefore, the final speed of the body is 15 m/s.
To find the speed of the body after being acted on by a force for a certain duration, we can use the equation:
Final velocity (v) = Initial velocity (u) + (Acceleration (a) × Time (t))
In this case, we are given the force (F) and mass (m) of the body, and we can use Newton's second law of motion to find the acceleration:
Force (F) = mass (m) × acceleration (a)
We can rearrange this equation to solve for acceleration:
Acceleration (a) = Force (F) / mass (m)
Substituting the given values:
Acceleration (a) = 18N / 6kg
Acceleration (a) = 3 m/s²
We can now use this acceleration to find the final velocity:
Final velocity (v) = Initial velocity (u) + (Acceleration (a) × Time (t))
Given:
Initial velocity (u) = 3m/s
Time (t) = 4 seconds
Substituting the values:
Final velocity (v) = 3m/s + (3 m/s² × 4s)
Final velocity (v) = 3m/s + 12m/s
Final velocity (v) = 15m/s
Therefore, the speed of the body after being acted on by the force for 4 seconds is 15 m/s.