1. A RADIO HUT QUALITY INSPECTOR EXAMINES A SAMPLE OF 50 RADIOS AND FINDS THAT 5 ARE DEFECTIVE. WHAT IS THE BEST PREDICTION OF THE NUMBER OF DEFECTIVE RADIOS IN A DELIVERY OF 200 RADIOS? *
195 radios
5 radios
20 radios
50 radios
prob(defect) = 5/50 = 1/10
so what is 1/10 of 200 ??
20?
of course.
To find the best prediction of the number of defective radios in a delivery of 200 radios, we can use the concept of proportion.
First, we need to determine the proportion of defective radios in the sample of 50. The proportion can be calculated by dividing the number of defective radios (5) by the total number of radios in the sample (50).
Proportion of defective radios = Number of defective radios / Total number of radios in the sample
= 5 / 50
= 0.1
This means that 0.1, or 10%, of the radios in the sample were defective.
Next, we can use this proportion to estimate the number of defective radios in a delivery of 200 radios. We multiply the proportion of defective radios in the sample (0.1) by the total number of radios in the delivery (200).
Number of defective radios in the delivery = Proportion of defective radios * Total number of radios in the delivery
= 0.1 * 200
= 20
Therefore, the best prediction of the number of defective radios in a delivery of 200 radios is 20 radios.
So the correct answer is: 20 radios.