how many intergers are there for numbers with tens greater or equal to 7 and for units less or equal to 4
15
Well, let me do some clown math here. If we're talking about integers, we'll need to consider both positive and negative numbers.
Let's start with the positive integers. If the tens digit is greater than or equal to 7, we have 3 options: 7, 8, and 9. And if the units digit is less than or equal to 4, we have 5 options: 0, 1, 2, 3, and 4. So, using the digits 7, 8, 9 for the tens and 0, 1, 2, 3, 4 for the units, there are 3 x 5 = 15 positive integers that fit the criteria.
Now, let's clown around with the negative integers. The same logic applies, but this time the tens digit will be less than or equal to -7, giving us the options -7, -8, and -9. And the units digit will still be less than or equal to 4, so we'll have the same 5 options. Multiply those together and we've got 3 x 5 = 15 negative integers as well.
Adding the positive and negative integers together, we have a grand total of 15 + 15 = 30 integers that fit the given criteria. Clown math for the win!
To find the number of integers that satisfy the given condition, we need to determine the range of tens and units that satisfy the condition.
The tens place can have digits from 7 to 9 (7, 8, 9), which is a total of three options.
The units place can have digits from 0 to 4 (0, 1, 2, 3, 4), which is a total of five options.
To find the total number of integers, we need to multiply the number of options for the tens digit by the number of options for the units digit:
Total number of integers = 3 (options for tens) × 5 (options for units) = 15.
Therefore, there are 15 integers that satisfy the condition.
To find the number of integers that satisfy the given conditions, we first need to determine the range of possible values for the tens digit and the units digit.
For the tens digit (t), it is specified that it must be greater than or equal to 7. This means the possible values for t are 7, 8, and 9.
For the units digit (u), it is specified that it must be less than or equal to 4. This means the possible values for u are 0, 1, 2, 3, and 4.
To find the number of integers, we need to consider all possible combinations of t and u. In this case, we need to multiply the number of possible values for t (3) by the number of possible values for u (5). This gives us:
3 × 5 = 15
Therefore, there are 15 integers that satisfy the given conditions.
Since you did not specify how large these integers could be,
there would be an infinite number of them.
However, if you restrict it to 2 digit integers, then the only possible
tens digit would be 7, 8, 9 and the only possible unit digits are 0, 1, 2, 3, and 4
so there would be 3*5 or 15 of them .
they would be easy to list:
70, 71, 72, 73, 74, 80, .... , 93, 94