if 14.00 mole of nitrogen N2 reacts with sufficient hydrogen H2 how many grams of ammonia NH3 would be produced
To determine the grams of ammonia produced, we need to use the balanced chemical equation for the reaction between nitrogen and hydrogen to produce ammonia. The equation is:
N2 + 3H2 → 2NH3
From the equation, we can see that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.
First, convert the given moles of N2 (14.00 mole) to moles of NH3.
Since the mole ratio of NH3 to N2 is 2:1, we can calculate:
14.00 moles of N2 * (2 moles of NH3 / 1 mole of N2) = 28.00 moles of NH3
Next, we need to convert moles of NH3 to grams. To do this, we need the molar mass of NH3. The molar mass of NH3 can be calculated as follows:
N: 14.01 g/mol
H: 1.01 g/mol (There are three H atoms in NH3)
So, the molar mass of NH3 = (14.01 g/mol) + (3 * 1.01 g/mol) = 17.03 g/mol
Now, we can calculate the grams of NH3:
28.00 moles of NH3 * 17.03 g/mol = 476.84 grams of NH3
Therefore, if 14.00 moles of nitrogen react with sufficient hydrogen, 476.84 grams of ammonia would be produced.