The velocity of a car (in miles per hour) is given by:
v(t)=36t−9t2
where t is in hours. Write a definite integral for the distance the car travels during the first 2.5 hours. Use your graphing calculator to find this distance.
∫ 36t - 9t^2 dt from 0 to 2.5
= [18t^2 - 3t^3] from 0 to 2.5
= (18(2.5)^2 - 3(2.5)^3 ) - (0 - 0) )
= .....
I would use the graphing calculator to 'VERIFY" the answer from above.